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Converters Constants Calculator Analytical Geometry
Circle Vectors Straight Line Parabola Ellipse Hyperbola
Coordinate Geometry [Triangle] Coordinate Geometry [Quadrilateral]
Operations:
Intersection of two circles
Intersection of a circle and a straight line
Equation of circumcircle of a triangle
Image of a circle
Equation of incircle of a triangle
Equation of excircles of a triangle
Equation of common chord of two circles
Parametric Equation of Circle
Chord of Contact of Circle

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OPERATIONS:

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Intersection of two circles
Intersection of a circle and a straight line
Equation of circumcircle of a triangle
Image of a circle
Equation of incircle of a triangle
Equation of excircles of a triangle
Equation of common chord of two circles
Parametric Equation of Circle
Chord of Contact of Circle
General Info
In Polar Coordinates
From two end-points of the diameter
Passing through three points
Touching both the axes
Passing through the origin
Touching a tangent and passing through a point
Passing through Intersecting point of two circles and another point
Passing through Intersecting point of circle and a straight line and another point
Chord Bisected at a Point
Having a center and a tangent

dialogs

Equation of a circle passing through the intersection points of other two circles and another point

Input the equations of the two circles.

In case of inputting square roots, press the square root button and activate it. To insert fractions, insert it converting into decimals. For example, \(\frac{3}{4}\) is to be inputted as \(0.75\). But the output will be in decimals. Again, for working with more irrational numbers like \(2+\sqrt3\), you must input it in decimal form using full-stop \((.)\) as the decimal point.

\(x^2+y^2+2gx+2fy+c=0\)

The circle has center \((-g, -f)\) and radius \(\sqrt{g^2+f^2-c}\).



Input the point through which the circle passes:







Theory [Equation of a circle passing through the intersection points of two circles and another point]


Consider that the equation of the two circles are \(g(x,y)\) and \(f(x,y)\). The third circle passes through the Intersecting points of these two circles, whose equation can be derived according to A. R. Khalifa Rule, which is: $$p(x,y)=g(x,y)+k.f(x,y)=0$$ The circle \(p(x,y)\) passes through an external point \((m,n)\) upon which none of the circles \(g(x,y)\) and \(f(x,y)\) passes through. Thus, we find \(k\): $$k=-\frac{g(m,n)}{f(m,n)}$$ Putting this k back into the former equation, we find our circle.

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